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=-0.4Y^2+8.3Y
We move all terms to the left:
-(-0.4Y^2+8.3Y)=0
We get rid of parentheses
0.4Y^2-8.3Y=0
a = 0.4; b = -8.3; c = 0;
Δ = b2-4ac
Δ = -8.32-4·0.4·0
Δ = 68.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8.3)-\sqrt{68.89}}{2*0.4}=\frac{8.3-\sqrt{68.89}}{0.8} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8.3)+\sqrt{68.89}}{2*0.4}=\frac{8.3+\sqrt{68.89}}{0.8} $
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